Question

In: Statistics and Probability

Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards...

Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with a standard deviation of 6. Let X be the number of Christmas cards received by a randomly selected American. Round all answers to 4 decimal places where possible.

a. What is the distribution of X? X ~ N(,)

b. If an American is randomly chosen, find the probability that this American will receive no more than 19 Christmas cards this year.  

c. If an American is randomly chosen, find the probability that this American will receive between 21 and 25 Christmas cards this year.  

d. 73% of all Americans receive at most how many Christmas cards? (Please enter a whole number)

Solutions

Expert Solution


Related Solutions

Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards...
Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with a standard deviation of 7. Let X be the number of Christmas cards received by a randomly selected American. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N(,) b. If an American is randomly chosen, find the probability that this American will receive no more than 24 Christmas cards this...
Americans receive an average of 22 Christmas cards each year. Suppose the number of Christmas cards...
Americans receive an average of 22 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with a standard deviation of 6. Let X be the number of Christmas cards received by a randomly selected American. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N(,) b. If an American is randomly chosen, find the probability that this American will receive no more than 25 Christmas cards this...
Up to 20% of Americans contract influenza each year. A sample of 400 randomly selected Americans...
Up to 20% of Americans contract influenza each year. A sample of 400 randomly selected Americans is chosen and the number with influenza is recorded. Let X represent the number with influenza in the sample. What is the probability that, at most, 25% of the sample is observed to have influenza? How can I do this the easiest way on Ti-84? Can I use a button like Stats or Distr to make life easy?
Suppose consumers spent $42 million on Christmas trees last year, when the average tree cost was...
Suppose consumers spent $42 million on Christmas trees last year, when the average tree cost was $30. This year they spend $42 million, when the average tree costs $25. Assume that everything else remains constant. This data suggests that:​ Select one: a. ​the demand for trees is inelastic. b. ​total revenue to tree producers rose this year. c. ​consumers bought the same number of Christmas trees this year as last year. d. ​the price of the Christmas trees stayed the...
1. Crestview sells a particularly popular Christmas card once a year and distributes the cards to...
1. Crestview sells a particularly popular Christmas card once a year and distributes the cards to gift shops. It costs Crestview $1 per card to order from a printing company, and Crestview receives $2 for each card sold. Each card that is not sold is discarded, and Crestview receives $0.1 for each. Crestview has estimated that the demand for the coming Christmas season follows a normal distribution with a mean of 100,000 and standard deviation of 30,000. a) Determine the...
Crestview sells a particularly popular Christmas card once a year and distributes the cards to gift...
Crestview sells a particularly popular Christmas card once a year and distributes the cards to gift shops. It costs Crestview $0.5 per card to order from a printing company, and Crestview receives $1.0 for each card sold. The printing company costs $0.30 to print each card. Because the cards have the current year printed on them, those cards that are not sold are discarded at no value. Crestview has estimated that the demand for the coming Christmas season follows a...
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do...
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do twenty-year-olds have a different number of cavities? The data show the results of a survey of 15 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 7, 6, 6, 4, 7, 6, 6, 5, 5, 5, 7, 4, 6, 5, 6 What can be concluded at the αα = 0.10 level of significance? For...
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do...
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do twenty-year-olds have more cavities? The data show the results of a survey of 13 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 4, 7, 4, 6, 5, 4, 5, 5, 5, 5, 5, 4, 4 What can be concluded at the αα = 0.01 level of significance? For this study, we should use...
Suppose you receive $100 at the end of each year for the nextthree years.What...
Suppose you receive $100 at the end of each year for the next three years.What is the future value in three years at 8% interest?
Suppose that the average number of a car accidents in a year was 10,276. The standard...
Suppose that the average number of a car accidents in a year was 10,276. The standard deviation for the same distribution was 2600. Calculate your answers to four decimal places and include the probability notation show all your work. A) suppose that you took a sample of 75 years, is the sampling distribution normally distributed? explain how you know? B) what is the mean and standard deviation for the sampling distribution of 75 years? C) what is the probability that...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT