In: Math
Data: 7,-5, -8, 7, 9, 15, 0, 2, 13, 8, 6, -2, 4 (a) Mean= Mode= median= (b) Variance= Standard deviation= (c) Range= IQR(Interquartilerange)= (d) Mid-Range= Mid-Hinge=
Solution:
Given that
x | x2 |
7 | 49 |
-5 | 25 |
-8 | 64 |
7 | 49 |
9 | 81 |
0 | 0 |
2 | 4 |
13 | 169 |
8 | 64 |
6 | 36 |
-2 | 4 |
4 | 16 |
x = 56 | x2 = 786 |
a ) The sample mean is
Mean = x/ n
= (7+-5 -8+7+ 9+15+ 0+2+13+ 8+ 6 -2+ 4 / 13 )
= 56 / 13
= 4.3077
The sample mean is = 4.3077
Mode :
In the given data, the observation 7 occurs maximum number of times
(2)
∴ Z = 7
Mode = 7
Median :
Observations in the ascending order are :
-8,-5,-2,0,2,4,6,7,7,8,9,13,15
M = Value of ( n + 1 / 2 )th Observations
= Value of ( 13 + 1 / 2 )th Observations
= Value of 7th Observations
= 6
Median = 6
b ) The Sample Variance is S2
S2 = ( x2 ) - (( x )2 / n ) / 1 -n )
= (786 (56 )2 / 13 ) / 12
= (786 - 541.2308 / 12 )
= (544.7692 / 12 )
= 45.3974
The Sample Variance is S2 = 45.3974
The sample standard is S
S = Sample Variance
= 45.3974
= 6.7378
The sample standard is S = 6.7378
C ) Range
Observations in the ascending order are :
-8,-5,-2,0,2,4,6,7,7,8,9,13,15
Range = maximum(xi) - minimum(xi
= 15 - 8
= 23
Range = 23.
IQR ( Inter quartilerange )
IQR= Upper quartile XU - Lower quartile
XL
= - 1 - 8.5
= 9.5
IQR ( Inter quartilerange ) = 9.5
(d) Mid-Range
Observations in the ascending order are :
-8,-5,-2,0,2,4,6,7,7,8,9,13,15
M = midrange
max = maximum value
min = minimum value
M = (max + min) / 2
M = (maximum value - minimum value / 2)
= (15 - 8 / 2 )
= 3.5
Mid-Range = 3.5
Mid-Hinge
Mid-Hinge = ( Q1 + Q3 / 2 )
= (- 1 + 8.5 / 2 )
= 3.75
Mid-Hinge = 3.75