Question
In: Math
A recent study reported that 51% of the children in a particular community were overweight or...
A recent study reported that 51% of the children in a particular community were overweight or obese. Suppose a random sample of 500 public school children is taken from this community. Assume the sample was taken in such a way that the conditions for using the Central Limit Theorem are met. We are interested in finding the probability that the proportion of overweight/obese children in the sample will be greater than 0.47. Complete parts (a) and (b) below. . Calculate the probability that 47% or more of the sample are overweight or obese.
Solutions
Expert Solution
Solution:
Given that,
n = 487
= 51% =0.51
1 - 
= 1 - 0.51 = 093
=
= 0.07
= 
( 1 -
) / n
=
= 0.0223
= 0.0223
p (
> 0.47 )
= 1 - p (
< 0.47 )
= 1 - p (
-
/
) < ( 0.47 - 0.51 / 0.0223 )
= 1 - p ( z < -0.01 / 0.0223 )
= 1 - p ( z < -1.79)
Using z table
= 1 - 0.0367
= 0.9633
Probability = 0.9633
milcah answered 2 years agoRelated Solutions
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