In: Statistics and Probability
An article reported that, in a study of a particular wafer
inspection process, 356 dies were examined by an inspection probe
and 154 of these passed the probe. Assuming a stable process,
calculate a 95% (two-sided) confidence interval for the proportion
of all dies that pass the probe. (Round your answers to three
decimal places.)
Solution :
Given that,
n = 356
x = 154
= x / n = 154 / 356 = 0.43
1 - = 1 - 0.43 = 0.57
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z / 2 * [( * (1 - )] / n)
= 1.96 * [(0.43 * 0.57)] / 356)
= 0.051
A 95% confidence interval for population proportion p is ,
- E < P < + E
0.43 - 0.051 < p < 0.43 + 0.051
0.379 < p < 0.481
(0.379, 0.481)