In: Chemistry
4. Calcium ion forms a weak 1:1 complex with nitrate ion with a formation constant of 2.0. What would the equilibrim concentrations of Ca2+ and Ca(NO3)+ in a solution prepared by adding 10.0 mL each of 0.010 M M CaCl2 and 2.0 M NaNO3? (neglect diverse ion effects).
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STANDARD REACTION OF FORMATION OF 1:1 COMPLEX
formation constant (Kf)....
......(1)
here, both reagents are strong ionic salt and both will 100 % ionize....
standard reaction is...
from stoichiometric coefficient value it is clear that 2 mole NaNO3 required 1 mole CaCl2.
here, mole of CaCl2 = molarity * vol in lit = 0.010 * 0.01 = 0.0001
mole of NaNO3 = 2 * 0.01 = 0.02
therefore, to complete the reaction 0.01 mole CaCl2 is required but only 0.0001 mole of CaCl2 is present. therefore, CaCl2 is the limiting reagent.
from the dissociation of CaCl2....the value of [Ca2+] will be = 0.010 M
and from dissociation of NaNO3... the value of [NO3-] will be = 2.0 M
from the above equation (1)...
or, [Ca(NO3)+] = 0.04 M