Question

1. 0.40 moles of cyclohexene, 0.35 moles of water and 0.45 moles of sulfuric acid are combined in a reaction flask. a. What is the limiting reagent of this reaction? b. What is the theoretical yield of cyclohexanol in moles and in grams?

2. 0.60 moles of cyclohexene, 0.80 moles of water and 0.70 moles of sulfuric acid are combined in a reaction flask. a. What is the limiting reagent of this reaction? b. What is the theoretical yield of cyclohexanol in moles and in grams?

GIVEN: Quantities: Theoretical yield: cyclohexene 20 ml 0.20 moles cyclohexanol: water 8 ml 0.44 moles 0.20 moles concentrated sulfuric acid 16 ml 0.30 moles

Answer 1

1.

a) Reaction take place as given below

C₆H₁₂ + H₂SO₄    C₆H₁₃-OSO₃H

C₆H₁₃-OSO₃H + H₂O C₆H₁₃-OH + H₂SO₄

According to reaction cyclohexene, water and sulfuric acid react in equimolar proportion thus all three required in equimolar proportion but water given only 0.35 mole therefore water is limiting reagent.

b) water is limiting reagent react completely thus 0.35 mole water produce 0.35 mole of hexanol.

molar mass of hexanol = 102.177 gm / mole then 0.35 mole of hexanol = 0.35 102.177 = 35.76 gm

theoretical yield = 0.35 mole = 35.76 gm

2.

a) Reaction take place as given below

C₆H₁₂ + H₂SO₄    C₆H₁₃-OSO₃H

C₆H₁₃-OSO₃H + H₂O C₆H₁₃-OH + H₂SO₄

According to reaction cyclohexene, water and sulfuric acid react in equimolar proportion thus all three required in equimolar proportion but cyclohexene given only 0.60 mole therefore cyclohexene is limiting reagent.

b) cyclohexene is limiting reagent react completely thus 0.60 mole cyclohexene produce 0.60 mole of hexanol.

molar mass of hexanol = 102.177 gm / mole then 0.60 mole of hexanol = 0.60 102.177 = 61.30 gm

theoretical yield = 0.60 mole = 61.30 gm