W + 2X <----> 5Y + 3Z 0.40 moles of W and 0.40 moles of X...

W + 2X <----> 5Y + 3Z

0.40 moles of W and 0.40 moles of X are placed into a 2.0 liter flask. At equilibrium, 0.70 moles of Y are present in the flask. Calculate the concentration of each specie at equilibrium and calculate the value of equilibrium constant.

Expert Solution

conc of W = no of moles/volume in L

= 0.4/2 = 0.2 M

conc of X = no of moles/volume in L

= 0.4/2 = 0.2M

conc of Y = no of moles/volume in L

= 0.7/2 = 0.35M

W + 2X <----> 5Y + 3Z

I 0.2 0.2 0 0

C -0.07 -2*0.07 5*0.07 3*0.07

E 0.13 0.06 0.35 0.21

[Y] = 0.35M

[Z] = 0.21M

[W] = 0.13M

[X] = 0.06M

Kc = [Y]^5*[Z]^3/[W][X]^2

= (0.35)^5*(0.21)^3/(0.13)(0.06)^2 = 0.104 >>>>answer

queen_honey_blossom answered 2 years ago

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