Question

In the reaction, 791.96 moles of barium chloride and unlimited amount of sulfuric acid react, to give, as products braium sulfate and hydrochloric acid. How much is the minimum amount of reactant required of sulfuric cud, in moles. Then additionally, how much product is produced of barium sulfate, in grams, and hydrochloric acid, in grams?

Answer 1

BaCl2   +   H2SO4 ----------------------> BaSO4 + 2 HCl

1 mole       1 mole                            1 mole        2 mole

791.96 mole    ?

a) moles of sulfuric acid reacted = 791.96

b)   moles of barium sulfate formed = 791.96

   mass of barium sulfate = moles x molar mass

                                        = 791.96 x 233.38

    mass of barium sulfate     = 1.85 x 10^5 g

c) moles of HCl = 2 x 791.96 = 1584 g

    mass of hydrochloric acid = 1584 x 36.5

   mass of hydrochloric acid = 5.78 x 10^4 g