In: Statistics and Probability
A production manager at a wall clock company wants to test their new wall clocks. The designer claims they have a mean life of 1717 years with a variance of 1616.
If the claim is true, in a sample of 4343 wall clocks, what is the probability that the mean clock life would be greater than 17.917.9 years? Round your answer to four decimal places.
Solution :
Given that ,
mean = = 17
variance 2 = 16
standard deviation = = 4
n = 43
= 17
= / n = 4/ 43 = 0.61
P( > 17.9) = 1 - P( <17.9 )
= 1 - P[( - ) / < (17.9-17) /0.61 ]
= 1 - P(z < 1.48)
Using z table
= 1 - 0.9306
= 0.0694
probability=0.0694