Question

In python find matrix M

I have the matrix X

X=[5.8   3.0    3.7    1.9]

and need to create a matrix M that is 4x150 that has the the values of matrix X inside it for every row

M=

5.8	3.0	3.7	1.9
5.8	3.0	3.7	1.9
5.8	3.0	3.7	1.9
5.8	3.0	3.7	1.9
5.8	3.0	3.7	ect
5.8	ect	ect
5.8
ect
5.8

Answer 1

The given matrix is:

X=[5.8   3.0    3.7    1.9]

We need to create one more matrix that has 150 rows and 4 columns and then will initialize the value from the matrix X to the newly created matrix.

The required program source code is given below:

import numpy as np

#create an array
X = np.array([5.8, 3.0, 3.7, 1.9])

#create a matrix
M = np.zeros((150, 4))

#initialize the matrix
for i in range(150):
for j in range(4):
M[i][j] = X[j]

#display the matrix
for i in range(150):
for j in range(4):
print(M[i][j],end=" ")
print()

The screenshot of the above source code is given below:

OUTPUT:

5.8     3.0     3.7     1.9                                                     

5.8     3.0     3.7     1.9                                                     

5.8     3.0     3.7     1.9                                                     

5.8     3.0     3.7     1.9                                                     

5.8     3.0     3.7     1.9

continue up to 150 rows...