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In: Computer Science

Q8. If the bits 0 and 2 of P1IN are set, then toggle all the bits...

Q8. If the bits 0 and 2 of P1IN are set, then toggle all the bits of P1OUT simultaneously except the bit 4, else toggle only the bit 4 of P1OUT.

Solutions

Expert Solution

Hello,

#include <msp430g2553.h>
volatile unsigned int i = 0;
void main(void)
{
WDTCTL = WDTPW + WDTHOLD;

   P1DIR |= BIT0;               // P1.0 output, BIT0 is define as (0x0001) in the header file
   P1OUT &= ~BIT0;            // P1.0 output LOW, LED Off

   P1DIR |= BIT6;                // P1.6 output
   P1OUT &= ~BIT6;            // P1.6 output LOW, LED Off

   for (;;)
   {
       P1OUT ^= BIT0 + BIT6; // Toggle LED at P1.0 and P1.6
                               // Here BIT1 and BIT6 added and relevant two bits will be toggled


       for(i=0; i< 20000; i++);   // Delay between LED toggles.
   }
}

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