In: Economics
Your company has two alternatives to consider for purchasing new heat treating ovens for hardening and annealing production metal assemblies. Details of each alternative are given below. Draw the cash flow diagram for each and assume your company’s MARR is 8%. Using a present value comparison which alternative do you recommend?
Alternative A: The TomKin Oven Company will sell your company 5 heat treating ovens with manual feeds and extraction mechanisms. The ovens will initially cost $18,000 each and have an estimated life of 7 years. They will all require insulation overhauls in year 4 costing $2,500 each. At the end of their life each oven is estimated to be worth $2,000. The ovens will result in tougher metal assemblies which is estimated to save the company $57,000 per year total in year 1 increasing by $3,500 per year total every year after year 1.
Alternative B: The Quickspeed Heat Treat Equipment Company will also sell your company 5 heat treating ovens but with automatic feeds and extraction mechanisms. The ovens will initially cost $25,000 each and have an estimated life of 7 years. They will not require any insulation overhauls but are each expected to have maintenance issues costing $700 each in year 1 and then increasing by $400 each for every year after year 1. At the end of their life, each oven is estimated to be worth $3,000. The ovens will result in tougher metal assemblies which is estimated to save the company $70,000 per year total in year 1 increasing by $4,100 per year total every year after year 1.
Alternative A
No. of Ovens= 5
Initial Cost =$18000
Total Initial Cost = 18000*5=$90000
Life 7 years
Overhaul cost in year 4 = $2500*5 = $12500
Salvage value = $2000*5 =$10000
Saving in Year 1 = $57000
Saving in Year 2 = 57000+3500 = 60500
Saving in Year 3 = 60500+3500 = 64000
Saving in Year 4 = 64000+3500 = 67500
Saving in Year 5 = 67500+3500 = 71000
Saving in Year 6 = 71000+3500 = 74500
Saving in Year 7 = 74500+3500 = 78000
Cashflow can be calculated as follows:
YR0 | YR1 | YR2 | YR3 | YR4 | YR5 | YR6 | YR7 | |
Initial Cost | -90000 | |||||||
Overhaul Cost | -12500 | |||||||
Salvage Value | 10000 | |||||||
Savings | 57000 | 60500 | 64000 | 67500 | 71000 | 74500 | 78000 | |
Total Cashflow | -90000 | 57000 | 60500 | 64000 | -12500+67500 | 71000 | 74500 | 10000+78000 |
Total Cashflow | -90000 | 57000 | 60500 | 64000 | 55000 | 71000 | 74500 | 88000 |
Total Present Value can be calculated as follows:
YR1 | YR2 | YR3 | YR4 | YR5 | YR6 | YR7 | ||
Total Cashflow | -90000 | 57000 | 60500 | 64000 | 55000 | 71000 | 74500 | 88000 |
Present Value | -90000 | =57000/(1+8%)^1 | =60500/(1+8%)^2 | =64000/(1+8%)^3 | =55000/(1+8%)^4 | =71000/(1+8%)^5 | =74500/(1+8%)^6 | =88000/(1+8%)^7 |
Present Value | -90000 | =57000/1.08 | =60500/1.08^2 | =64000/1.08^3 | =55000/1.08^4 | =71000/1.08^5 | =74500/1.08^6 | =88000/1.08^7 |
Present Value | -90000 | =57000/1.08 | =60500/1.1664 | =64000/1.260 | =55000/1.3605 | =71000/1.4693 | =74500/1.5869 | =88000/1.7138 |
Present Value | -90000 | 52777.78 | 51869.00 | 50805.26 | 40426.64 | 48321.41 | 46947.64 | 51347.15 |
Total Present Value | =-90000+52777.78+51869+50805.26+40426.64+48321.41+46947.64+51347.15 | |||||||
Total Present Value | 252494.9 |
Alternative B
No. of Ovens= 5
Initial Cost =$25000
Total Initial Cost = 25000*5=$125000
Life 7 years
Maintenance cost in each year = $700*5 = $3500 with increase of 400*5=$2000 every year
Maintenance cost in Year 2 = 3500+2000= 5500
Maintenance cost in Year 3 = 5500+2000 = 7500
Maintenance cost in Year 4 = 7500+2000 = 9500
Maintenance cost in Year 5 = 9500+2000 = 11500
Maintenance cost in Year 6 = 11500+2000 = 13500
Maintenance cost in Year 7 = 13500+2000 = 15500
Salvage value = $3000*5 =$15000
Saving in Year 1 = $70000
Saving in Year 2 = 70000+4100 = 74100
Saving in Year 3 = 74100+4100 = 78200
Saving in Year 4 = 78200+4100 = 82300
Saving in Year 5 = 82300+4100 = 86400
Saving in Year 6 = 86400+4100 = 90500
Saving in Year 7 = 90500+4100 = 94600
Cashflow can be calculated as follows:
YR0 | YR1 | YR2 | YR3 | YR4 | YR5 | YR6 | YR7 | |
Initial Cost | -125000 | |||||||
Maintenance Cost | -3500 | -5500 | -7500 | -9500 | -11500 | -13500 | -15500 | |
Salvage Value | 15000 | |||||||
Savings | 70000 | 74100 | 78200 | 82300 | 86400 | 90500 | 94600 | |
Total Cashflow | -125000 | 66500 | -5500+74100 | -7500+78200 | -9500+82300 | -11500+86400 | -13500+90500 | -15500+15000+94600 |
Total Cashflow | -125000 | 66500 | 68600 | 70700 | 72800 | 74900 | 77000 | 94100 |
Total Present Value can be calculated as follows:
YR1 | YR2 | YR3 | YR4 | YR5 | YR6 | YR7 | ||
Total Cashflow | -125000 | 66500 | 68600 | 70700 | 72800 | 74900 | 77000 | 94100 |
Present Value | -125000 | =66500/(1+8%)^1 | =68600/(1+8%)^2 | =70700/(1+8%)^3 | =72800/(1+8%)^4 | =74900/(1+8%)^5 | =77000/(1+8%)^6 | =94100/(1+8%)^7 |
Present Value | -125000 | =66500/1.08 | =68600/1.08^2 | =70700/1.08^3 | =72800/1.08^4 | =74900/1.08^5 | =77000/1.08^6 | =94100/1.08^7 |
Present Value | -125000 | =66500/1.08 | =68600/1.1664 | =70700/1.260 | =72800/1.3605 | =74900/1.4693 | =77000/1.5869 | =94100/1.7138 |
Present Value | -125000 | 61574.07 | 58813.44 | 56111.11 | 53509.74 | 50976.65 | 48522.28 | 54907.22 |
Total Present Value | =-125000+61574.07+58813.44+56111.11+53509.74+50976.65+48522.28+54907.22 | |||||||
Total Present Value | 259414.51 |
Since Present value of Alternate B is more it shall be chosen