In: Finance
When purchasing a $260,000 house, a borrower is comparing two loan alternatives. The first loan is a 90% loan at 8.5% for 25 years. The second loan is an 85% loan for 7.75% over 15 years. Both have monthly payments and the property is expected to be held over the life of the loan. What is the incremental cost of borrowing the extra money?
could you please show the work
Solution:
To find the incremental cost of borrowing the extra money,we should calculate the total payment under both loan
a)Calculation of total payment under 90% Loan amount
Loan Amount=$260,000*90%=$234,000
Monthly interest rate(r)=8.50/12=0.71% or 0.0071
No. of payment(n)=25*12=300
Monthly Payment=Loan Amount[r(1+r)^n/((1+r)^n-1)]
=$234000[0.0071(1+0.0071)^300/((1+0.0071)^300-1)]
=$1884.23
Total payment=Monthly payment*No. of payment
=$1884.23*300
=$565,269
Interest=$565,269-$$234,000
=$331,269
b)Calculation of total payment under 85% Loan amount
Loan amount=$260,000*85%=$221,000
Monthly interest rate(r)=7.75%/12=0.65% or 0.0065
No. of payment(n)=15*12=180
Monthly Payment=Loan Amount[r(1+r)^n/((1+r)^n-1)]
=$221,000[0.0065*(1+0.0065)^180/(1+0.0065)^180-1]
=$2080.22
Total payment=Monthly payment*No. of payment
=$2080.22*180
=$374,439.60
Interest=$374,439.60-$221,000
=$153,439.60
c)Thus,incremental cost of borrowing the extra money is;
=Interest under 90% loan amount-Interest under 85% Loan amount
=$331,269-$153,439.60
=$177,829.40