Question

Create a program that ask to input two users and the result will vary on their name with similar digits. In a game of F.L.A.M.E.S , it will count and repeat depends on their name that has a similar digit. For an Example (JOE RIZAL) and (JACKLYN BRACKEN) - JOE RIZAL has - 5 similar digits , while JACKLYN BRACKEN has 6 similar digits so a total of 11.

F - Friends - 1,7

L - Lover - 2,8

A - Anger - 3,9

M - Married - 4,10

E - ENEMY - 5,11 - therefore joe rizal and jacklyn are soulmate

S - SOULMATE - 6

use looping , switch statement , toupper , tolower , string , swap and much more...

// SAMPLE OUTPUT //

INPUT YOUR FULLNAME: JOE RIZAL

INPUT YOUR PARTNER FULL NAME: JACKLYN BRACKEN

RESULTS: JOE RIZAL AND JACKLYN BRACKEN ARE ENEMY.

Answer 1

#include<iostream>
#include<string.h>
#include<ctype.h>
using namespace std;
int main()
{
   int count1=0,count2=0,count;
   string s1,s2;
   cout<<"Enter first name\t";
   getline(cin,s1);
   cout<<"enter second name\t";
   getline(cin,s2);
   int len1= s1.length();
   int len2= s2.length();
   for(int i=0;i<len1;i++)
   {
       if(islower(s1[i]))
           s1[i]=toupper(s1[i]);
       for(int j=0;j<len2;j++)
       {
           if(islower(s2[j]))
           s2[j]=toupper(s2[j]);
           if(s1[i]==s2[j])
           {
               ++count1;
               break;
           }
       }
   }
   for(int i=0;i<len2;i++)
   {
       if(islower(s2[i]))
           s2[i]=toupper(s2[i]);  
       for(int j=0;j<len1;j++)
       {
           if(islower(s1[j]))
           s1[j]=toupper(s1[j]);
           if(s2[i]==s1[j])
           {
               ++count2;
               break;
           }
       }
   }
   count1--;//space is also counted, so decrease one.
   count2--;//space is also counted so decrease one.
   count=count1+count2;
   if(count==0){
   cout<<"NO MATCH FOUND";
   }
   else{
   count=(count%6);
   switch(count)
   {
       case 1:
               cout<<"FRIENDS";
               break;
              
       case 2:
               cout<<"LOVER";
               break;
      
       case 3:
               cout<<"ANGER";
               break;
      
       case 4:
               cout<<"MARRIED";
               break;
      
       case 5:
               cout<<"ENEMY";
               break;
      
       case 0:
               cout<<"SOULMATE";
               break;
   }
   }
}

OUTPUT:

Enter first name JOE rizal
enter second name JACKlyn bracKEN
ENEMY
--------------------------------
Process exited after 29.72 seconds with return value 0
Press any key to continue . . .