Question

Ag2So4(s)-->2Ag+(aq)+SO42- (q)

initial .844mmol----> 0 1.697x10^-2

change: -x ----->2x 1.697X10^-2+x

eq. .844-x-----> 2x 1.697x10^-2+x

KSp=1.40x10^-9

Answer 1

         Ag2SO4(s) <====> 2Ag+(aq)    +     SO4^2-(aq)

I       0.844 mmol                   -                  1.697 x 10^-2 mmol

C         -x                            +2x                         +x mmol

E    (0.844-x)mmol             +2x              (1.697 x 10^-2 - x)mmol

Ksp = [Ag+]^2[SO4^2-]

1.40 x 10^-9 = (2x)^2(1.697 x 10^-2 - x)

x being a small number

1.40 x 10^-9 = (2x)^2(1.697 x 10^-2)

molar solubility of salt in solution,

x = 1.44 x 10^-4 M