Question

In: Statistics and Probability

1. Flip a fair coin ten times. Find the probability of at least seven heads. 2....

1. Flip a fair coin ten times. Find the probability of at least seven heads.

2. Draw five cards at once from a deck. Find the probability of getting two pairs.

3. Roll a die infinitely times. Find the probability that you see an even number before you see an one.

4. You and your friend take turns to draw from an urn containing one green marble and one hundred blue marbles, one at a time and you keep the marble. Whoever draw the green marble wins. Suppose you draw first. What is the probability that you win?

Solutions

Expert Solution

1

When a fair coin is tossed probability of getting a head is p = 0.50.

Let X is a random variable shows the number of heads in 10 tosses. Here X has binomial distribution with parameters as follows:

n =10 and p=0.5

The probability of at least seven heads is

2:

There are total 13 denominations and each denomination has 4 cards. So number of ways of selecting 2 denominations and then 2 cards out of 4 is


And since we need exactly 2 pairs so remaining 1 card must come from different denomination so number of ways of selecting 1 denominations out of remaining 11 denominations and then 1 card from selected denomination is


So number of ways of selecting 2 pairs is :


So required probability is


Related Solutions

Flip a fair coin 5 times. What is the probability that at least one time the...
Flip a fair coin 5 times. What is the probability that at least one time the coin lands on heads?
If you flip a fair coin, the probability that the result is heads will be 0.50....
If you flip a fair coin, the probability that the result is heads will be 0.50. A given coin is tested for fairness using a hypothesis test of H0:p=0.50 versus HA:p≠0.50. The given coin is flipped 180 times, and comes up heads 110 times. Assume this can be treated as a Simple Random Sample. The test statistic for this sample z and the p value
Flip a fair coin 4 times. Let ? and ? denote the number of heads and...
Flip a fair coin 4 times. Let ? and ? denote the number of heads and tails correspondingly. (a) What is the distribution of ?? What is the distribution of ? ? (b) Find the joint PMF. Are ? and ? independent? (c) Calculate ?(? ?) and ?(X≠?)(d) Calculate C??(?, ? ) and C???(?, ? )
We flip a fair coin 20 times. Find the probability that we obtain between 8 and...
We flip a fair coin 20 times. Find the probability that we obtain between 8 and 17 heads, inclusively. Show work and please explain to someone that hardly understands statistics!
Flip a fair coin 100 times. Let X equal the number of heads in the first...
Flip a fair coin 100 times. Let X equal the number of heads in the first 65 flips. Let Y equal the number of heads in the remaining 35 flips. (a) Find PX (x) and PY (y). (b) In a couple of sentences, explain whether X and Y are or are not independent? (c) Find PX,Y (x, y).
Every day you flip a fair coin four times and if it is heads all four...
Every day you flip a fair coin four times and if it is heads all four times, you give a dollar to charity. In a year with 365 days, what is your expected annual donation to charity and what is the variance?
If a fair coin is tossed 25 times, the probability distribution for the number of heads,...
If a fair coin is tossed 25 times, the probability distribution for the number of heads, X, is given below. Find the mean and the standard deviation of the probability distribution using Excel Enter the mean and round the standard deviation to two decimal places. x   P(x) 0   0 1   0 2   0 3   0.0001 4   0.0004 5   0.0016 6   0.0053 7   0.0143 8   0.0322 9   0.0609 10   0.0974 11   0.1328 12   0.155 13   0.155 14   0.1328 15   0.0974 16  ...
A coin is flipped seven times. What is the probability of getting heads six or fewer...
A coin is flipped seven times. What is the probability of getting heads six or fewer times? I know how to solve this with the probability equation. 2x2x2x2x2x2x2=128 total outcomes Which is p1+p2=1 -> p1=1-p2-=1-1/128= 127/128 is the answer. But whenever I try to solve it with the permutation formula I get a wrong answer n!/ k!(n!-k!) = 7!/6!(7!-6!) = 7 7/128 where am I wrong? can someone explain to me what am I doing wrong?
1. A) If you flip an unfair coin 100 times, and the probability for a coin...
1. A) If you flip an unfair coin 100 times, and the probability for a coin to be heads is 0.4, then the number of heads you expect on average is: B) If you flip an unfair coin 100 times, and the probability for a coin to be heads is 0.4, then the standard deviation for the number of heads is: C) If you flip an unfair coin 2 times, and the probability for a coin to be heads is...
Flip a coin 10 times. Put a 1 each time the coin comes up heads and...
Flip a coin 10 times. Put a 1 each time the coin comes up heads and a 0 each time the coin comes up tails. Count the number of heads you obtained and divide by 10. What number did you get? a. Is the number you obtained in part (a) a parameter or a statistic? b. Now flip the coin 25 times. Put a 1 each time you obtain a heads and a 0 for tails. Count the number of...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT