In: Statistics and Probability
When making inferences concerning the mean difference using two dependent samples, it is necessary to calculate the standard deviation of the sample differences.
Calculate the standard deviation of the sample differences using the following information.
Round to 2 decimal places.
College Placement Test Results
Applicant | 1 | 2 | 3 | 4 | 5 |
Before | 51 | 62 | 74 | 64 | 72 |
After | 68 | 87 | 82 | 75 | 84 |
Solution:
First, we will calculate the differences of all applicants which
can be calculated as
Applicant |
Before |
After |
Differences(Before - After) |
1 |
51 |
68 |
-17 |
2 |
62 |
87 |
-25 |
3 |
74 |
82 |
-8 |
4 |
64 |
75 |
-11 |
5 |
72 |
84 |
-12 |
Now we will calculate differences mean which can be calculated
as
Dbar =
Difference/n = (-17-25-8-11-12)/5 = -73/5 = -14.6
So standard deviation of difference can be calculated as
Standard deviation (Sd) = sqrt(((Di-Dbar)^2)/(n-1))
= sqrt((-17-(-14.6))^2 + (-25-(-14.6))^2 + (-8-(-14.6))^2 +
(-11-(-14.6))^2 + (-12-(-14.6))^2)/4)
Applicant |
Before |
After |
Differences(Before - After) |
Di-mean |
(Di-mean)^2 |
1 |
51 |
68 |
-17 |
-2.4 |
5.76 |
2 |
62 |
87 |
-25 |
-10.4 |
108.16 |
3 |
74 |
82 |
-8 |
6.6 |
43.56 |
4 |
64 |
75 |
-11 |
3.6 |
12.96 |
5 |
72 |
84 |
-12 |
2.6 |
6.76 |
Sd = sqrt((5.76+108.16+43.56+12.96+6.76)/4) = sqrt(177.2/4) = sqrt(43.3) = 6.66
standard deviation of the sample differences = 6.66