In: Physics
How much energy is produced when the sun converts 8 kg into helium and energy?(hint: how does this problem differ from when the sun converts 8 kg of mass into energy)
Solution:-Since 1 gram of hydrogen atoms is equal to its one mole.
So number of moles in 8kg(8000 gram)=8000 moles
No. of atoms per mole=Avagadro number=6.022x1023
So total number of hydrogen atoms in 8kg i.e. in 8000 moles=8000x6.022x1023
=4.8176x1027
Since during nuclear fusion inside the sun four Hydrogen atoms convert into single He atom and energy released due to mass difference between reactants and product masses.
So number of He atoms form by such number of hydrogen atoms
Mass of 1 hydrogen atlom=1.00794 AMU
so mass of 4 hydrogen atoms=4x1.00794=4.03176 AMU
now mass of 1 He atom =4.002602 AMU
So mass reduction when 4 hydrogen is converted into 1 helium
=4.03176-4.002602
=0.029158 AMU
Since number of He atom formed by 8 kg hydrogen is 1.2044x1027
So total mass reduction=0.029158 x1.2044x1027
=3.51179x1025 AMU
=3.51179x1025x1.66x10-27Kg
=5.82957x10-2Kg
Now released energy
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Now if 8kg mass directly converted into energy then amount of energy released-