Question

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Answer 1

Given,

Dish soap specific weight(w₁)= 9.14 kN/m³

Golf Ball Specific weight(w₂)= 10.83 kN/m³

Brine specific weight(w₃)= 12.0 kN/m³

statements,a) golf ball sinks to the bottom of the container that has only dishwashing liquid.

b) golf ball floats or is not fully submerged in the container that contains only the brine.

Let consider golf ball volume is = V m³

Now weight of the galf ball(W₂) =10.83V kN

weight of the displaced dish soap fluid when it is sinked inside (W₁)=9.14V kN

weight of the displaced brine when it is sinked inside (W₃)=12.0V kN

Using Archimedes' principle ,i.e. Buoyant force Object weight (Object floats), otherwise sinks.

As we can see W₂W₁ , then statement a is correct

W₂W₃, then statement b is also correct.

If the dish washing fluid is added to the ball,brine system the it would reduce the fluid density(as w₁w₃). As a result bouyent force would be weaker than previous one and finally galf ball goes down and sink completely, when the fluid mixture specific weight reduced to the specific weight of the galf ball material(w₂).

If data of the fluid volumes were given, then it can be measured that how much dish wash fluid should be mixed with brine.