Four point masses are arranged as follows: m1 = 5.76 g at (0,19.6 cm), m2 =...

Four point masses are arranged as follows: m1 = 5.76 g at (0,19.6 cm), m2 = 2.25 g at (19.6, 0) cm, m3 = m1 at (0,-19.6) cm and m4 = m2/.49 at (-19.6, 0) cm. These are all immovable

a) In unit vector notation, what is the net gravitational force from them on a point with mass m5 = 2.56 g at the origin?

b) If m5 was free to move and released from rest what will its speed be after travelling 9.8 cm?

c) Imagine a new configuration where m2 has been removed. What would then be the new answer to part b?

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Expert Solution

Universal gravitational force is employed here.Using equations of motion v2=u2+2as we can find the velocity of the particle.

genius_generous answered 10 months ago

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