Question

Write a function average_steps(step_records) that takes a list of records, ie, tuples in the form (date_str, step_count), and returns the average number of steps made across all the records as an unrounded floating point number.

If step_records is an empty list then None should be returned.

Note: You should include and use your total_steps function.

Test	Result
step_records = [('2010-01-01',1), ('2010-01-02',2), ('2010-01-03',3)] avg = average_steps(step_records) print(avg)	2.0
step_records = [] avg = average_steps(step_records) print(avg)	None
step_records = [('2010-01-01',3), ('2010-01-02',3), ('2010-01-03',3), ('2010-01-04',3), ('2010-01-05',3)] avg = average_steps(step_records) print(avg)	3.0

Answer 1

#source code:

def total_steps(p):
   return p
def average_steps(step_records):
   c=0
   sum=0
   total=0
   for i in range(len(step_records)):
       total=total_steps(i+1)
       sum=sum+step_records[i][1]
   if(total==0):
       return None
   else:
       return sum/total
      
      
step_records=[('2010-01-01',1),('2010-01-02',2),('2010-01-03',3)]
avg=average_steps(step_records)
print(avg)

step_records=[]
avg=average_steps(step_records)
print(avg)

step_records=[('2010-01-01',3),('2010-01-02',3),('2010-01-03',3),('2010-01-04',3),('2010-01-05',3)]
avg=average_steps(step_records)
print(avg)

#output:

#if you have any doubt comment below...