In: Statistics and Probability
A marketing firm surveys 11 people to see how much they like a certain perspective advertisement on a 0 to 10 scale. The following were the responses of the 11 people: { 4, 3, 2, 7, 5, 6, 1, 4, 3, 9, 0}. Find the approximate 95% confidence interval for the population mean. What is the lower bound? SHOW ALL STEPS
Solution:
Given in the question
Responses of the 11 people are as follows:
4,3,2,7,5,6,1,4.3,9,0
First, we will calculate Sample mean and observations as
follows:
Sample mean = (4+3+2+7+5+6+1+4+3+9+0)/11 = 44/11 = 4
n = 11
Sample standard deviation(S) =
sqrt(summation(Xi-mean)^2/(N-1))
X | Xi-mean | (Xi-mean)^2 |
4.00 | 0.00 | 0 |
3.00 | -1.00 | 1 |
2.00 | -2.00 | 4 |
7.00 | 3.00 | 9 |
5.00 | 1.00 | 1 |
6.00 | 2.00 | 4 |
1.00 | -3.00 | 9 |
4.00 | 0.00 | 0 |
3.00 | -1.00 | 1 |
9.00 | 5.00 | 25 |
0.00 | -4.00 | 16 |
Standard deviation = sqrt(0+1+4+9+1+4+9+0+1+25+11)/10) =
sqrt(70/10) = sqrt(7) = 2.65
So 95% confidence interval for a population mean can be calculated
as
Mean +/- talpha/2*S/sqrt(n)
alpha = 0.05, alpha/2 = 0.025 and df= 11-1 = 10 so talpha/2 from t
table is 2.2281
Mean +/- talpha/2*S/sqrt(n)
4 +/- 2.2281*2.65/sqrt(11)
4+/- 1.78
So 95% confidence interval is 2.22 to 5.78
And lower bound for 95% confidence interval is 2.22