The native and denatured forms of a protein are generally in equilibrium as follows: &

The native and denatured forms of a protein are generally in equilibrium as follows:

Protein (denatured) <--> Protein (native)

For a certain solution of the protein ribonuclease A, in which the total protein concentration is 2.00 x 10^-3 M, the concentrations of the denatured and native proteins at both 25.0°C and 37.0°C are given in the following table.

Temperature (C°)	[Ribonuclease A (denatured)] (M)	[Ribonuclease A (native)] (M)
25.0	5.10 x 10^-6	2.00 x 10^-3
37.0	2.80 x 10^-4	1.70 x 10^-3

a. Determine ∆G°, ∆H° and DS° for the folding reaction at 27.0° C assuming that it is independent of temperature.

b. What is the denaturation temperature of ribonuclease A under standard state conditions? (This is the temperature at which the K_eq = 1.00)

please answer b- I know the answer to a, but have no idea how to approach b

Solutions

Expert Solution

b) I shall need the calculations for part (a). I will tell you how to do it though.

You have said that you got part (a) correct which means that you have found out numeric values for ΔG⁰, ΔH⁰ and ΔS⁰.

You need to assume that ΔH⁰ and ΔS⁰ are independent of temperature, i.e, whatever numeric values you have for ΔH⁰ and ΔS⁰ will stay constant throughout.

You are given that K_eq = 1.000; find out ΔG⁰ using the relation ΔG⁰ - -R*T*ln K_eq where T is the desired temperature.

We know that ln (1.000) = 0 and hence, ΔG⁰ = 0.

Next use the relation

ΔG⁰ = ΔH⁰ – T*ΔS⁰ = 0

====> T = ΔH⁰/ΔS⁰

Simply divide the value of ΔH⁰ by the value of ΔS⁰ obtained in part (a) and you will get T; hope this helps.

queen_honey_blossom answered 1 year ago

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