Question
In: Statistics and Probability
1. Is there sufficient evidence to conclude that there is a difference in the mean number...
1. Is there sufficient evidence to conclude that there is a
difference in the mean number of hours of tv watched for those that
reported active lifestyle vs those that did not?
DATA:
Equal variances assumed
F=4.997
Sig.=.025
t= .420
df=4998
Sig. (2-tailed)= .675
Mean difference= .49823
Std. Error difference= .51551
Lower=-.51256
Upper= 1.50903
Equal Variances not assumed
t=-.421
df= 4966.401
Sig. (2-tailed)=.674
Mean difference= -.062
Std. Error difference= .146
Lower=-.348
Upper= .225
95% confidence interval
a. should they reject or retain?
b. calculate the effect size
c. interpret the effect size in the context of the
situation
Solutions
orchestra answered 1 year agoRelated Solutions
1. Is there sufficient evidence to conclude that there is a difference in the mean age...
1.
Is there sufficient evidence to conclude that there is a difference
in the mean age of male customers vs female customers?
DATA
Equal variances assumed
F= 1.572
Sig=.210
t= .370
df= 4998
Sig. (2- tailed)= .712
Mean difference= .185
Std. Error difference= .501
Lower= -.797
Upper= 1.167 95% confidence Interval
Equal variances not assumed
t= .370
df= 4992. 696
Sig. (2-tailed)= .712
Mean difference= .185
Std. Error difference= .501
Lower= .797
Upper= 1.167
a. should they reject or retain?...
Is there sufficient evidence to conclude that there is a mean difference in mile time for...
Is there sufficient evidence to conclude that there is a mean
difference in mile time for runners when they had coffee with
breakfast vs without?
PAIRED SAMPLES TEST
Pair 1 coffee-nocoffee
Mean=-.31585
Std. Deviation= .52660
Std. Error mean=.08326
Lower=-.48427
Upper= -.14744
t= -3.793
df=39
Sig. (2-tailed)=.001
a. Should they reject or retain? Give numerical
justification
b. Calculate the effect size
c. Interpret the effect size in the context of the
situation
marriages Mean: 182916.67 standard Deviation: 43928.57 n= 12 Determine if there is sufficient evidence to conclude...
marriages
Mean: 182916.67
standard Deviation: 43928.57
n= 12
Determine if there is sufficient evidence to conclude the
average amount of marriages is greater or equal to 2500 in the
United States and territories at the .05 level of significance.
1. Clearly state a null and alternative hypothesis
2. Give the value of the test statistic
3. Report the P-Value
4. Clearly state your conclusion (Reject the Null or Fail to Reject
the Null)
5. Explain what your conclusion means in...
Determine if there is sufficient evidence to conclude the average amount of deaths is equal to...
Determine if there is sufficient evidence to conclude the
average amount of deaths is equal to 6000 in the United States and
territories at the 0.10 level of significance.
Summary Table for Deaths
AVERAGE
4,292
MEDIAN
3,085
STANDARD DEVIATION
4292.71585
MAX
20,895
MIN
316
Clearly state a null and alternative hypothesis
Give the value of the test statistic n=52
Report the P-Value
Clearly state your conclusion (Reject the Null or Fail to
Reject the Null)
Explain what your conclusion means...
Determine if there is sufficient evidence to conclude the average amount of deaths is equal to...
Determine if there is sufficient evidence to conclude the
average amount of deaths is equal to 6000 in the United States and
territories at the 0.10 level of significance. N=52
Clearly state a null and alternative hypothesis
Give the value of the test statistic
Report the P-Value
Clearly state your conclusion (Reject the Null or Fail to
Reject the Null)
Explain what your conclusion means in context of the data.
Summary Table for Deaths
Mean
4,001
Median
2,961
Standard Deviation...
Determine if there is sufficient evidence to conclude the average amount of marriages is greater or...
Determine if there is sufficient evidence to conclude the
average amount of marriages is greater or equal to 2500 in the
United States and territories at the .05 level of
significance. N=52
Clearly state a null and alternative hypothesis
Give the value of the test statistic
Report the P-Value
Clearly state your conclusion (Reject the Null or Fail to
Reject the Null)
Explain what your conclusion means in context of the data.
Summary Table for Marriages
Mean
3,801
Median
3,000...
Determine if there is sufficient evidence to conclude the average amount of births is over 5000...
Determine if there is sufficient evidence to conclude the
average amount of births is over 5000 in the United States and
territories at the 0.05 level of significance.
Summary Table for Live Births
AVERAGE
6,833
MEDIAN
4,781
STANDARD DEVIATION
8039.02237
MAX
45,231
MIN
537
Clearly state a null and alternative hypothesis
Give the value of the test statistic n= 52
Report the P-Value
Clearly state your conclusion (Reject the Null or Fail to
Reject the Null)
Explain what your conclusion...
Determine if there is sufficient evidence to conclude the average amount of divorces is less than...
Determine if there is sufficient evidence to conclude the
average amount of divorces is less than or equal to 4000 in the
United States and territories at the 0.10 level of
significance.
Clearly state a null and alternative hypothesis
Give the value of the test statistic
Report the P-Value
Clearly state your conclusion (Reject the Null or Fail to
Reject the Null)
Explain what your conclusion means in context of the data.
using this data sample size is 52
Summary...
Determine if there is sufficient evidence to conclude the average amount of divorces is greater than...
Determine if there is sufficient evidence to conclude the
average amount of divorces is greater than or equal to 3000 in the
United States and territories at the 0.05 level of significance
N=52.
Clearly state a null and alternative hypothesis
Give the value of the test statistic
Report the P-Value
Clearly state your conclusion (Reject the Null or Fail to
Reject the Null)
Explain what your conclusion means in context of the data.
Summary Table for Divorces
Mean
1,399
Median...
Determine if there is sufficient evidence to conclude the average amount of births is over 5000...
Determine if there is sufficient evidence to conclude the
average amount of births is over 5000 in the United States and
territories at the 0.05 level of significance. Mean-6206,
Median- 4260.5, Standard Deviation- 7419.46802,
Min- 444, Max-42,836
Determine if there is sufficient evidence to conclude the
average amount of deaths is equal to 6000 in the United States and
territories at the 0.10 level of significance.Mean-3877,
Median- 2698, Standard Deviation- 3950.91464, Min-
323, Max-7684
Determine if there is sufficient evidence...
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