Question

Write a function name as 'checkEvenOrOdd' that checks the input value is odd or even number. The main function is given:

int main(){

    int number;

    cout << "Check number input: ";

    cin >> number;

    cout << "The input number " << number << " is " << checkEvenOrOdd(number) << endl;

    return 0;

}

simple c++ code please

Answer 1

The function checkEvenorOdd() is highlighted in the following code

% gives the remainder. If n%2 gives remainder 0 then it is even else it is odd

Code:

#include <iostream>
using namespace std;

char* checkEvenOrOdd(int n){
if(n % 2 == 0)
return "Even";
else
return "Odd";
}
int main(){
int number;
cout << "Check number input: ";
cin >> number;
cout << "The input number " << number << " is " << checkEvenOrOdd(number) << endl;
return 0;
}

Sample O/P1:

Check number input: 23
The input number 23 is Odd

Sample O/P2:

Check number input: 16
The input number 16 is Even

Code Screenshot:

Sample O/P1 screenshot:

Sample O/P2 screenshot: