Question

In: Chemistry

In the gas phase, N2O5 decomposes according to the following reaction 2N2O5 (g) --> 4NO2 (g)...

In the gas phase, N2O5 decomposes according to the following reaction

2N2O5 (g) --> 4NO2 (g) + O2 (g)

We put some N2O5 (g) in a container and it has a pressure of 0.154 atm. After the reaction proceeds for 103 seconds, the total pressure has increased to 0.260 atm. Assuming constant temperature and volume, the average rate of disappearance of the N2O5 (g) during this time interval is

answer is: 1.0 x 10^-3 atm/s

Please show work :D

Solutions

Expert Solution

In the gas phase, N2O5 decomposes according to the following reaction

2N2O5 (g) --> 4NO2 (g) + O2 (g)

We put some N2O5 (g) in a container and it has a pressure of 0.154 atm. After the reaction proceeds for 103 seconds, the total pressure has increased to 0.260 atm. Assuming constant temperature and volume, the average rate of disappearance of the N2O5 (g) during this time interval is

Solution

We will be calculating rate of disappearance of N2O5 during 103 seconds.

Average rate is given by = Change in pressure/Change in time

                = 0.260 atm-0.154 atm/103 sec

                = 0.106 atm/103 sec

                                             = 0.001 atm/sec

Answer is: 1.0 x 10^-3 atm/s

queen_honey_blossom answered 2 years ago
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