Question

In: Chemistry

consider the reaction 4NO2(g) + O2(g) ---> 2N2O5(g) At a particular time during the reaction, nitrogen...

consider the reaction 4NO2(g) + O2(g) ---> 2N2O5(g) At a particular time during the reaction, nitrogen dioxide is being consumed at the rate of 0.0013 M/s. At what rate is molecular oxygen being consumed?

Solutions

Expert Solution

Rate eq for the reaction:

4NO2(g) + O2(g) ---> 2N2O5(g)

-1/4d[NO2]/dt = -d[O2]/dt = +d[N2O5]/dt

From here:

rate of consumption of molecular oxygen:     d[O2]/dt = 1/4d[NO2]/dt

                                                                              = 0.0013/4

                                                                              = 0.000325 = 3.25 x 10-4 M/s


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