In: Chemistry
Could you please answer this?
The reaction of Cr3+(aq) and Cr(s) to form Cr2+(aq). [The reduction potential of Cr2+(aq)to Cr(s) is -0.91 V.]
Calculate ΔG∘rxn.
Calculate K
Cr^3+(aq) + Cr(s) ---------------------> Cr^2+ (aq)
Cr(s) ----------------------> Cr^2+ (aq) + 2e^+ E0 = 0.91v
2Cr^3+ (aq) + 2e^- -----------> 2Cr^2+ (aq) E0 = -0.407v
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2Cr^3+(aq) + Cr(s) ---------------------> 3Cr^2+ (aq) Ecell = 0.503v
n = 2
G0 = -nE0cell *F
= -2*0.503*96500
= -97079J
G0 = -RTlnK
-97079 = -8.314*298*2.303logK
-97079 = -5705.8483logK
logK = -97079/-5705.8483
logK = 17
K = 10^17 = 1*10^17 >>>>answer