In: Chemistry
Solution :-
Given data
Time = (11.0 hours * 60 min / 1 hr )*(60 sec / 1 min ) =39600 sec
Current = 50 A
Mass of Chromium deposited= ?
We are given with the current and time
Therefore using the current and time lets first calculate the charge in coloumb (C)
Charge = current * time
Lets put the values in the formula
Charge (C) = 50 A * 39600 sec
= 1980000 C
Now using the charge lets calculate the moles of electrons
1 mole e- = 96500 C
? mol e- = 1980000 C
1980000 C * 1 mol e- / 96500 C = 20.52 mol e-
Now using the moles of electrons lets calculate the moles of the Cr deposited.
Cr^2+ + 2e- -------- > Cr(s)
1 mol Cr = 2 mol e-
20.52 mol e- * 1 mol Cr / 2 mol e- = 10.26 mol Cr
Now lets convert moles of Cr to its mass
Mass = moles * molar mass
Mass of Cr= 10.26 mol * 51.996 g per mol
= 533 g Cr
Therefore mass of the Cr deposited on the electrode = 533 g