Question

In: Chemistry

Compare the number of moles of nitrogen-oxygen species in air containing 300 ppbv nitric oxide, with...

Compare the number of moles of nitrogen-oxygen species in air containing 300 ppbv nitric oxide, with fog consisting of 10,000 droplets per cm^3, having an average diameter of 2 um, and containing nitrate ion at a concentration of 3 * 10^5 moles L-1

Solutions

Expert Solution

1 m3 = 1000 L contains

10 000 droplets/ cm3 x 1000 cm3/L x 1000 L/ m3 x (4/3) x 3.14 x 1 x 10-18 m3 /doplet =

   = (4/3) x 3.14 x 10-8 m3 droplet volume / m3 air

    = 4.18 x 10-5 L droplets with [NO3-] = 3 x 10-5 mol/L

The number of NO3- mol in 1 m3 air is

3 x 10-5 mol/L x 4.18 x 10-5 L = 1.25 x 10-9 NO3- mol

300 ppb (volume) = 300 x 10-9 L NO/ L air

300 x 10-9 L NO/ L air x 1000 L air = 3.00 x 10-4L      ( 0.3 mL)

3.00 x 10-4L / 22.4 L/mol = 1.34x10-5 mol NO in 1 m3 air

                                                                                   

1.34x10-5 mol NO in 1 m3 air / 1.25 x 10-9 mol NO3- in 1 m3 air = 1.07 x 104

There are about 10 700 more NO mol in air than NO3- mol in the fog


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