Question

In: Physics

Mechanical Advantage Solution(Mastering Physics Chapter 04: Force and Motion)

The pulley system shown in the figure is used to lift a 52-kg crate. Note that one chain connects the upper pulley to the ceiling and a second chain connects the lower pulley to the crate. Assume the masses of the chains, pulleys, and ropes are negligible.

Part A

Determine the force F required to lift the crate with constant speed.

Part B

Determine the tension in the upper chain.

Part C

Determine the tension in the lower chain.

Solutions

Expert Solution

Part A

Since this is a pulley system, we have to count the number of “ropes” involved. There are two halves of rope on the pulley holding up the block, so the amount of force required for each is one half the total. The total force is just mass times gravity:

2T = mg
2T = 52 * 9.8
T = 254.8 N

254.8 N

Part B

The chains are not part of the pulley system. Each chain is subject to the same magnitude of force as the gravitational force on the block:

T = mg
T = 509.6 N

509.6 N

Part C

This is the same as in Part B (509.6 N)

509.6 N

Dr. OWL answered 4 years ago
Next > < Previous

Related Solutions

Mechanical Advantage Solution(Mastering Physics Chapter 04: Force and Motion)
A 6 kg bucket of water is being pulled straight up by a string at a constant speed. Part A What is the tension in the rope? Part B At a certain point the speed of the bucket begins to change. The bucket now has an upward constant acceleration of magnitude 3 m/s2. What is the tension in the rope now? Part C Now assume that the bucket has a downward acceleration, with a constant acceleration of magnitude 3 m/s2.
Pushing a Lawnmower Solution(Mastering Physics Chapter 04: Force and Motion)
Consider a lawnmower of weight w which can slide across a horizontal surface with a coefficient of friction μ. In this problem the lawnmower is pushed using a massless handle, which makes an angle theta with the horizontal. Assume that Fh, the force exerted by the handle, is parallel to the handle. Take the positive x direction to be to the right and the postive y direction to be upward. Part A Find the magnitude, Fh, of the force required...
A Book on a Table Solution(Mastering Physics Chapter 04: Force and Motion)
A book weighing 5 N rests on top of a table. Part A  A downward force of magnitude 5 N is exerted on the book by the force of the table gravity inertia Part B An upward force of magnitude _____ is exerted on the _____ by the table. 6 N / table 5 N / table 5 N / book 6 N / book Part C Do the downward force in Part A and the upward force in Part...
Suspending a Speaker Solution(Mastering Physics Chapter 04: Force and Motion)
A loudspeaker of mass 24.0 kg is suspended a distance of h = 1.00 below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 3.10. Part A What is the tension T in each of the cables?Use 9.80 m/s2 for the magnitude of the acceleration due to gravity.
A Gymnast on a Rope Solution(Mastering Physics Chapter 04: Force and Motion)
A gymnast of mass 50.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Part A Calculate the tension T in the rope if the gymnast hangs motionless on the rope.Express your answer in newtons. Part B Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate.Express your answer in newtons. Part C Calculate the tension...
Hanging Chandelier Solution(Mastering Physics Chapter 04: Force and Motion)
A chandelier with mass m is attached to the ceiling of a large concert hall by two cables. Because the ceiling is covered with intricate architectural decorations (not indicated in the figure, which uses a humbler depiction), the workers who hung the chandelier couldn’t attach the cables to the ceiling directly above the chandelier. Instead, they attached the cables to the ceiling near the walls. Cable 1 has tension T1 and makes an angle of θ1 with the ceiling. Cable...
Question 4.12 Solution(Mastering Physics Chapter 04: Force and Motion)
Part A The kinematic equation x = x0 + V0t + 1/2at2 can be used: Only with constant velocities. Only with constant forces. With variable accelerations. All of the preceding
Question 4.10 Solution(Mastering Physics Chapter 04: Force and Motion)
Part A A brick hits a glass window. The brick breaks the glass, so: The magnitude of the force of the brick on the glass is greater than the magnitude of the force of the glass on the brick. The magnitude of the force of the brick on the glass is equal to the magnitude of the force of the glass on the brick. The magnitude of the force of the brick on the glass is smaller than the magnitude...
Question 4.4 Solution(Mastering Physics Chapter 04: Force and Motion)
Part A If the net force on an object is zero, the object could: Have zero acceleration. Be at rest. Be in motion at a constant velocity. All of the preceding
Motion of a Block with Three Forces Solution(Mastering Physics Chapter 04: Force and Motion)
The diagram below shows a block of mass m = 2.0 kg on a frictionless horizontal surface, as seen from above. Three forces of magnitudes F1 = 4.0 N, F2 = 6.0 N, and F1 = 8.0 N are applied to the block, initially at rest on the surface, at angles shown on the diagram. In this problem, you will determine the resultant (total) force vector from the combination of the three individual force vectors. All angles should be measured...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT