Question

In: Statistics and Probability

Suppose a new treatment for a certain disease is given to a sample of 190 patients....

Suppose a new treatment for a certain disease is given to a sample of 190 patients. The treatment was successful for 151 of the patients. Assume that these patients are representative of the population of individuals who have this disease. Calculate a 98% confidence interval for the proportion successfully treated. (Round the answers to three decimal places.) Question: ____to____

Expert Solution

Solution :

Given that,

Point estimate = sample proportion = = x / n = 151 / 190 = 0.795

1 - = 1 - 0.795 = 0.205

Z/2 = 2.326

Margin of error = E = Z / 2 * $\sqrt$ (( * (1 - )) / n)

= 2.326 * ( $\sqrt$ ((0.795 * 0.205) / 190)

Margin of error = E = 0.068

A 98% confidence interval for population proportion p is ,

- E < p < + E

0.795 - 0.068 < p < 0.795 + 0.068

0.727 < p < 0.863

(0.727 to 0.863)

orchestra answered 2 years ago

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