Question

In: Physics

A tennis ball rolls off a vertical cliff at a projection angle of zero degrees to...

A tennis ball rolls off a vertical cliff at a projection angle of zero degrees to the horizontal (no initial vertical motion upwards) with a horizontal velocity of 11.52 m/s. If the cliff is -25 m high, calculate the horizontal distance in metres out from the base of the cliff that the ball will land.

Solutions

Expert Solution

The upwards direction is taken as positive and the downwards direction as negative.

Gravitational acceleration = g = -9.81 m/s2

Initial horizontal velocity of the ball = Vx = 11.52 m/s

Initial vertical velocity of the ball = Vy = 0 m/s (No vertical motion)

Height of the cliff = H = -25 m

Time taken by the ball to reach the ground = T

T = 2.258 sec

Horizontal distance traveled by the ball = R

There is horizontal force acting on the ball therefore the horizontal velocity of the ball remains constant.

R = VxT

R = (11.52)(2.258)

R = 26.01 m

Horizontal distance from the base of cliff to the point where the ball will land = 26.01 m


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