Question

In an online viral video, a truck rolls down an incline and off a vertical cliff, falling into a valley below. The truck starts from rest and rolls down the incline, which makes an angle of 21.0° below the horizontal, with a constant acceleration of 3.37 m/s². After rolling down the incline a distance of 30.0 m, it reaches the edge of the cliff, which is 35.0 m above ground level.

How much time (in s) does it take the truck to fall from the edge of the cliff to the landing point? _____

At the point where the truck crashes into the ground, how far is it horizontally from the edge of the cliff (in m)? _____

Answer 1

# The time taken by the truck to fall from the edge of the cliff to the landing point is 2.20 s.

## At the point where the truck crashes into the ground, the horizontal distance from the edge of the cliff is 29.19 m

Summary: We have to calculate the velocity of the truck at the edge of the cliff, as the initial velocity and the acceleration is given. Now, with the vertical component of this velocity, the truck will fall from the edge of cliff to the ground in time(t). After calculating the vertical component of velocity and as we know the height of the cliff and the gravitational acceleration, we can calculate the required time to fall from the edge of the cliff to the landing point.

To find the horizontal distance of the crashing point of the car from the base of the cliff, we have to multiply the horizonal component of velocity and time.