Question

Create a program that has an array of length 100 which will automatically be filled with randomly generated numbers between 1 and 100 each time the program is run. Have the program ask the user to enter a number between 1 and 100. Check to see if that number is one of the values in the array. If it is display “We found your number XX at position YY in the array” If the number is not in the array tell the user that no match was found.

Answer 1

Program:

#include<iostream>
#include <ctime>
#include <cstdlib>

using namespace std;

int main()
{
   //declare an array of size 100
   int myArray[100];
   int i,num,index;
   bool found=false;
  
   srand (time(NULL));
  
   //fill the array with random numbers between 1 and 100
   for(i=0;i<100;i++)
   {
       myArray[i]=rand() % 100 + 1;
   }
  
   //read a number from the user
   cout<<"\nEnter a number between 1 and 100: ";
   cin>>num;
  
   //loop through the array
   for(i=0;i<100;i++)
   {
       //check if array number matches with the user number, if match found store the index and set found to true
       if(myArray[i]==num)
       {
           index=i;
           found=true;
       }
   }
  
   //if match found print the position where the number is found in the array
   if(found)
       cout<<"\nWe found your number "<<num<<" at position "<<(index+1)<<" in the array.";
   //else print match not found
   else
       cout<<"\nNo match found.";
      
   return 0;
}

Output: