In: Statistics and Probability
4. Data were collected on student teachers relative to their use of certain teaching strategies that had been presented to them in preservice education. There were 28 student teachers who had learned to use the strategies (9 in 1979, 9 in 1980, and 10 in 1981). In 1978 there were 6 teachers who did not learn to use the strategies, and they were used as a control group. The investigator recorded the average number of strategies used per week by each of the student teachers during their student teaching assignments. The investigator wanted to know whether the number of strategies used by the student teachers was different among the years.
Average Number of Different Strategies Used |
|||
Control 1978 |
1979 |
1980 |
1981 |
6.88 |
7.25 |
10.85 |
7.29 |
5.4 |
10.5 |
7.43 |
14.38 |
16 |
8.43 |
6.71 |
6 |
9.8 |
8.63 |
7.6 |
5 |
7.63 |
8.63 |
7.6 |
5.38 |
5 |
7 |
5.57 |
14.14 |
11.13 |
8.71 |
9.25 |
|
7.25 |
5.86 |
5.71 |
|
10.38 |
7.2 |
7.35 |
|
10.75 |
e. Compute the 95 % confidence interval estimates of the treatment means.
f. Test the hypothesis of no differences among means of the four treatments with the F test at the .05 level of significance.
g. Write the normal equations for the data.
Ans:
e.Compute the 95 % confidence interval estimates of the treatment means.
Please see the discriptive summary with 95% confidence interval below and treatment means are highlited in yellow color.
1978 | 1979 | 1980 | 1981 | |
Mean | 8.452 | 8.800 | 7.503 | 8.525 |
Standard Error | 1.665 | 0.514 | 0.525 | 1.110 |
Median | 7.255 | 8.630 | 7.430 | 7.320 |
Mode | #N/A | 7.250 | 7.600 | #N/A |
Standard Deviation | 4.078 | 1.543 | 1.575 | 3.509 |
Sample Variance | 16.633 | 2.382 | 2.480 | 12.312 |
Kurtosis | 2.567 | -1.450 | 1.928 | -0.662 |
Skewness | 1.586 | 0.357 | 1.113 | 0.876 |
Range | 11.000 | 4.130 | 5.280 | 9.380 |
Minimum | 5.000 | 7.000 | 5.570 | 5.000 |
Maximum | 16.000 | 11.130 | 10.850 | 14.380 |
Sum | 50.710 | 79.200 | 67.530 | 85.250 |
Count | 6.000 | 9.000 | 9.000 | 10.000 |
Largest(1) | 16.000 | 11.130 | 10.850 | 14.380 |
Smallest(1) | 5.000 | 7.000 | 5.570 | 5.000 |
Confidence Level(95.0%) | 4.280 | 1.186 | 1.210 | 2.510 |
f. Test the hypothesis of no differences among means of the four treatments with the F test at the .05 level of significance.
Please see the Ftest summary at .05 level of significance below
F-Test | 1978 | 1979 | 1980 | 1981 |
Mean | 8.452 | 8.800 | 7.503 | 8.525 |
Variance | 16.633 | 2.382 | 2.480 | 12.312 |
Observations | 6.000 | 9.000 | 9.000 | 10.000 |
df | 5.000 | 8.000 | 8.000 | 9.000 |
F | 6.983 | 0.201 | ||
P(F<=f) one-tail | 0.009 | 0.017 | ||
F Critical one-tail | 3.687 | 0.295 |
g. Write the normal equations for the data?
Normal Equation is an analytical approach to Linear Regression with a Least Square Cost Function. We can directly find out the value of θ without using Gradient Descent. Following this approach is an effective and a time-saving option when are working with a dataset with small features.
Normal Equation is a follows :
In the above equation,
θ : hypothesis parameters that define it the
best.
X : Input feature value of each instance.
Y : Output value of each instance.