In: Statistics and Probability
If μ = 100, σ = 12, and n = 16, then use the t distribution to evaluate the probability ?̅ exceeds 103? Express your answer as a percentage with 3 decimals. |
Solution :
mean =
= 100
standard deviation =
= 12
n = 16
=
= 100
=
/
n = 12 /
16 = 3
P(
> 103) = 1 - P(
< 103)
= 1 - P[(
-
) /
< (103 - 100) / 3]
= 1 - P(z < 1)
Using z table,
= 1 - 0.8413
= 0.1587
The percentage is 15.87%