In: Statistics and Probability
If u = 100, sigma = 12, and n = 16, then use the t distribution to evaluate the probability ? exceeds 103?
Express your answer as a percentage with 3 decimals
Solution :
mean = 
 = 100
standard deviation = 
 = 12
n = 16

=  
= 100

= 
 / 
n = 12 / 
16 = 3
P(
> 103) = 1 - P(
< 103)
= 1 - P[(
- 
) / 
< (103 - 100) / 3]
= 1 - P(z < 1)
Using z table,
= 1 - 0.8413
= 0.1587
The percentage is 15.87%