Question
In: Statistics and Probability
The weekly demand for Papa’s pizzas on a Friday night is a normally distributed random variable...
- The weekly demand for Papa’s pizzas on a Friday night is a
normally distributed random variable with mean 222 and standard
deviation 8. Show your work.
- Find the probability that demand exceeds 220.
- Find the probability that demand is between 230 and 245.
- Find the probability that demand less than 240.
- Find the value of X for the lowest 25 percent.
- Suppose the store wants to make sure they are able to meet demand 90% of the time, how many pizzas should they bake?
Solutions
orchestra answered 1 year agoRelated Solutions
Weekly demand at a grocery store for a brand of breakfast cereal is normally distributed with...
Weekly demand at a grocery store for a brand of breakfast cereal
is normally distributed with a mean of 850 boxes and a standard
deviation of 80 boxes
b)
What is the probability that weekly demand is: Less than 900
boxes?
More than 1020 boxes?
Less than 660 boxes or greater than 980 boxes?
The weekly output of a steel mill is a uniformly distributed random variable that lies between...
The weekly output of a steel mill is a uniformly
distributed random variable that lies between 110 and 175 metirc
tons. 1. Compute the probability that the steel mill will produce
more than 150 metric tons next week. 2. Determine the probability
that the steel mill will produce between 120 and 160 metric tons
next week.
The demand for a certain weekly magazine at a newsstand is a discrete random variable, X....
The demand for a certain weekly magazine at a newsstand is a
discrete random variable, X. The demand never exceeds 6 magazines
per week. The distribution of X is symmetric about the value of
3.
1. The table below is intended to present the distribution of
variable X. Complete the table. x 0 1 2 3 4 5 6 P(X = x) 0.05 0.10
0.20
x
0
1
2
3
4
5
P(X=x)
0.05
0.10
0.20
2. The magazines cost...
For a random variable that is normally distributed, with μ = 80 and σ = 10,...
For a random variable that is normally distributed, with μ = 80
and σ = 10, determine the probability that a simple random sample
of 25 items will have a mean between 78 and 85?
a.
83.51%
b.
15.87%
c.
99.38%
d.
84.13%
5. A random variable is not normally distributed, but it is mound shaped. It has a...
5. A random variable is not normally distributed, but it
is mound shaped. It has a mean of 14 and a standard deviation of 3.
(Section 6.5)
a.) If you take a sample of size 10, can you say what
the shape of the sampling
distribution for the sample mean is? Why?
b.) For a sample of size 10, state the mean of the
sample mean and the standard deviation of the sample
mean.
c.) If you take a sample...
X is a random variable which is normally distributed with a mean of 99.01 and a...
X is a random variable which is normally distributed with a mean
of 99.01 and a standard deviation of 15.56. Use the Excel function
NORMINV to determine the required value of Xo to two decimal
places. Give your answer in the form xx.xx. P(X < Xo) =
0.0344
Answer:
A random variable is normally distributed with a mean of 24 and a standard deviation of...
A random variable is normally distributed with a mean of 24 and
a standard deviation of 6. If an observation is randomly selected
from the distribution,
a. What value will be exceeded 5% of the time?
b. What value will be exceeded 90% of the time?
c. Determine two values of which the smaller has 20% of the
values below it and the larger has 20% of the values above it.
d. What value will 10% of the observations be...
The following random sample of weekly student expenses in dollars is obtained from a normally distributed...
The following random sample of weekly student expenses in
dollars is obtained from a normally distributed population of
undergraduate students with unknown parameters.
8
56
76
75
62
81
72
69
91
84
49
75
69
59
70
53
65
78
71
87
71
74
69
65
64
You have been charged to conduct a statistical test in SPSS to
verify the claim that the‘average weekly student expenses’ is
different than 74 dollars using an alpha level of 5%.
...
The weight of a small Starbucks coffee is a normally distributed random variable with a mean...
The weight of a small Starbucks coffee is a normally distributed
random variable with a mean of 340 grams and a standard deviation
of 11 grams. Find the weight that corresponds to each event. (Use
Excel or Appendix C to calculate the z-value. Round your
final answers to 2 decimal places.)
highest 30 percent
middle 70 percent
highest 90 percent
lowest 20 percent
The weight of a small Starbucks coffee is a normally distributed random variable with a mean...
The weight of a small Starbucks coffee is a normally distributed
random variable with a mean of 415 grams and a standard deviation
of 23 grams. Find the weight that corresponds to each event.
(Use Excel or Appendix C to calculate the z-value.
Round your final answers to 2 decimal places.)
a.
Highest 20 percent
b.
Middle 60 percent
to
c.
Highest 80 percent
d.
Lowest 15 percent
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