Question

In: Statistics and Probability

Test a model that tries to explain differences in BMI based on parents' average BMI, a...

Test a model that tries to explain differences in BMI based on parents' average BMI, a person's age, number of weekly hours of exercise, and the number of times a person eats outside.

Which independent variable (IV) does not explain variability in a person's BMI? Explain.

Observation BMI Average parents' BMI Age Weekly Exercise Number of times eating outside
1 24 28 34 4 3
2 26 33 23 3 4
3 30 30 56 0 3
4 32 28 45 1 4
5 27 25 65 2 2
6 34 38 34 0 6
7 19 22 54 6 0
8 22 28 65 6 0
9 25 30 35 4 3
10 34 37 24 0 6
11 30 35 19 0 6
12 27 30 24 1 5
13 29 25 23 0 5
14 34 30 32 0 6
15 19 24 54 5 0
16 25 24 36 4 3
17 28 25 52 3 3
18 19 25 65 4 0
19 25 30 34 2 3
20 30 28 54 1 5
21 31 29 65 1 5
22 16 15 35 7 0
23 19 20 23 6 0
24 26 25 56 3 2
25 34 28 45 0 6
26 33 39 65 0 4
27 29 37 34 1 4
28 32 35 32 0 6
29 22 27 54 5 0
30 27 30 36 3 2
31 24 22 52 4 1

Solutions

Expert Solution

Solution:

Here our Dependent variable(Y) = BMI

And Independent Variables :

X1=Average parents BMI

X2=Age

X3=Weekly Exercise

X4=Number of times eating outside.

Here , we will perform Multiple Regression in SPSS.

Our Entered data :

Case Summariesa

Observation

Y

X1

X2

X3

X4

1

24

28

34

4

3

2

26

33

23

3

4

3

30

30

56

0

3

4

32

28

45

1

4

5

27

25

65

2

2

6

34

38

34

0

6

7

19

22

54

6

0

8

22

28

65

6

0

9

25

30

35

4

3

10

34

37

24

0

6

11

30

35

19

0

6

12

27

30

24

1

5

13

29

25

23

0

5

14

34

30

32

0

6

15

19

24

54

5

0

16

25

24

36

4

3

17

28

25

52

3

3

18

19

25

65

4

0

19

25

30

34

2

3

20

30

28

54

1

5

21

31

29

65

1

5

22

16

15

35

7

0

23

19

20

23

6

0

24

26

25

56

3

2

25

34

28

45

0

6

26

33

39

65

0

4

27

29

37

34

1

4

28

32

35

32

0

6

29

22

27

54

5

0

30

27

30

36

3

2

31

24

22

52

4

1

To perform Multiple regression in SPSS

Steps : Analyse ---Regression---Linear---Dependent(Y)---Independent(X1,X2,X3,X4)---method(stepwise)---Ok ---Statistics(tick estimates,model fit,descriptive)--- Save(tick unstandarised predicted and unstandardised residual)---Ok

Descriptive Statistics

Mean

Std. Deviation

N

Y

26.84

5.139

31

X1

28.45

5.501

31

X2

42.74

14.944

31

X3

2.45

2.234

31

X4

3.13

2.187

31

Model Summaryd

Model

R

R Square

Adjusted R Square

Std. Error of the Estimate

Change Statistics

R Square Change

F Change

df1

df2

Sig. F Change

1

.931a

.868

.863

1.902

.868

190.048

1

29

.000

2

.944b

.890

.882

1.762

.023

5.791

1

28

.023

3

.956c

.914

.904

1.589

.024

7.408

1

27

.011

ANOVAa

Model

Sum of Squares

df

Mean Square

F

Sig.

1

Regression

687.314

1

687.314

190.048

.000b

Residual

104.880

29

3.617

Total

792.194

30

2

Regression

705.289

2

352.645

113.620

.000c

Residual

86.904

28

3.104

Total

792.194

30

3

Regression

723.999

3

241.333

95.550

.000d

Residual

68.195

27

2.526

Total

792.194

30

from the above anova table all the model 1,2,3 are  significant to explain change in dependent variable Y i.e. BMI.

Coefficientsa

Model

Unstandardized Coefficients

Standardized Coefficients

t

Sig.

B

Std. Error

Beta

1

(Constant)

32.092

.512

62.711

.000

X3

-2.143

.155

-.931

-13.786

.000

2

(Constant)

27.810

1.841

15.103

.000

X3

-1.430

.329

-.622

-4.340

.000

X4

.810

.336

.345

2.407

.023

3

(Constant)

21.902

2.733

8.013

.000

X3

-.977

.341

-.425

-2.868

.008

X4

1.425

.378

.606

3.765

.001

X2

.067

.025

.195

2.722

.011

Our fitted Model :

Y= 21.902+0.067*X2-0.977*X3+1.425*X4

where,

X2=Age

X3=Weekly Exercise

X4=Number of times eating outside.

so , from the above regression analysis we have seen that only Independent variable X1=Average parents BMI

does not explain variability in Dependent variable.


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