In: Statistics and Probability
Students in a business statistics course performed a completely randomized design to test the strength of four brands of trash bags. One-pound weights were placed into a bag, one at a time, until the bag broke. A total of 40 bags, 10 for each brand, were used. The data in give the weight (in pounds) required to break the trash bags. Dataset: Trashbags
Kroger | Glad | Hefty | TuffStuff |
34 | 32 | 33 | 26 |
30 | 42 | 34 | 18 |
40 | 34 | 32 | 20 |
38 | 36 | 40 | 15 |
36 | 32 | 40 | 20 |
30 | 40 | 34 | 20 |
30 | 36 | 36 | 17 |
42 | 43 | 34 | 18 |
36 | 30 | 32 | 19 |
38 | 38 | 34 | 20 |
(a) The hypothesis being tested is:
H0: µ1 = µ2 = µ3 = µ4
Ha: At least one means is not equal
Source | DF | Adj SS | Adj MS | F-Value | P-Value |
Factor | 3 | 1986.5 | 662.16 | 48.11 | 0.000 |
Error | 36 | 495.5 | 13.76 | ||
Total | 39 | 2482.0 |
The p-value is 0.000.
Since the p-value (0.000) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that there is a difference in the mean strength of the four brands of trash bags.
(b) Using the Tukey Method and 95% Confidence
Factor | N | Mean | Grouping | |
Glad | 10 | 36.30 | A | |
Kroger | 10 | 35.40 | A | |
Hefty | 10 | 34.900 | A | |
TuffStuff | 10 | 19.300 | B |
Means that do not share a letter are significantly different.
(c) The hypothesis being tested is:
Null hypothesis | All variances are equal |
Alternative hypothesis | At least one variance is different |
Significance level | α = 0.05 |
Test
Method | Test Statistic |
P-Value |
Multiple comparisons | — | 0.576 |
Levene | 1.46 | 0.242 |
The p-value is 0.242.
Since the p-value (0.242) is greater than the significance level (0.05), we cannot reject the null hypothesis.
Therefore, we can conclude that there is no difference in the variation in strength among the four brands of trash bags.