In: Statistics and Probability
Develop the analysis of variance computations for the following completely randomized design. At α = 0.05, is there a significant difference between the treatment means?
Treatment | |||
---|---|---|---|
A | B | C | |
135 | 106 | 93 | |
120 | 114 | 82 | |
114 | 124 | 84 | |
106 | 104 | 102 | |
132 | 107 | 90 | |
115 | 108 | 117 | |
128 | 96 | 110 | |
102 | 115 | 120 | |
104 | 99 | ||
82 | 93 | ||
xj |
119 | 106 | 99 |
sj2 |
143.71 | 128.67 | 173.56 |
State the null and alternative hypotheses.
H0: Not all the population means are
equal.
Ha: μA =
μB =
μCH0:
μA ≠ μB ≠
μC
Ha: μA =
μB =
μC H0:
At least two of the population means are equal.
Ha: At least two of the population means are
different.H0: μA =
μB = μC
Ha: μA ≠
μB ≠
μCH0:
μA = μB =
μC
Ha: Not all the population means are equal.
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Do not reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal.Reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal. Do not reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.Reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.
The statistical software output for this problem is :
H0: At least two of the population means are
equal.
Ha: At least two of the population means are
different.
Test statistics = 6.04
P-value = 0.0072
Reject H0. There is sufficient evidence to conclude that the means of the three
treatments are not equal.