Question
In: Physics
A block of mass 5 kg is sitting on a frictionless surface. The block initially has...
A block of mass 5 kg is sitting on a
frictionless surface. The block initially has a velocity of
3 m/s. A force of 9 N is applied
for 2 s.
What is the Initial momentum of the block?
kg m/s
| Tries 0/2 |
What is the Initial Kinetic Energy of the
block?
J
| Tries 0/2 |
What is the change in momentum of the block?
Kg m/s
| Tries 0/2 |
What is the final momentum of the block?
kg m/s
| Tries 0/2 |
What is the final velocity of the block?
m/s
| Tries 0/2 |
What is the final Kinetic Energy of the block?
J
Solutions
Expert Solution
Mass of the block = m = 5 kg
Initial velocity of the block = V1 = 3 m/s
Initial momentum of the block = P1
Initial kinetic energy of the block = E1
Force applied on the block = F = 9 N
Time period the force is applied = T = 2 sec
Impulse of the force on the block = I
Change in momentum of the block = 
Impulse on an object is equal to the change in momentum of the object.
Final momentum of the block = P2
Final velocity of the block = V2
Final kinetic energy of the block = E2
a) Initial momentum of the block = 15 kg.m/s
b) Initial kinetic energy of the block = 22.5 J
c) Change in momentum of the block = 18 kg.m/s
d) Final momentum of the block = 33 kg.m/s
e) Final velocity of the block = 6.6 m/s
f) Final kinetic energy of the block = 108.9 J
genius_generous answered 1 year agoRelated Solutions
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