Question

In: Physics

A block of mass 5 kg is sitting on a frictionless surface. The block initially has...

A block of mass 5 kg is sitting on a frictionless surface. The block initially has a velocity of 3 m/s. A force of 9 N is applied for 2 s.

What is the Initial momentum of the block?

kg m/s

Tries 0/2

What is the Initial Kinetic Energy of the block?

J

Tries 0/2

What is the change in momentum of the block?

Kg m/s

Tries 0/2

What is the final momentum of the block?

kg m/s

Tries 0/2

What is the final velocity of the block?

m/s

Tries 0/2

What is the final Kinetic Energy of the block?

J

Solutions

Expert Solution

Mass of the block = m = 5 kg

Initial velocity of the block = V₁ = 3 m/s

Initial momentum of the block = P₁

Initial kinetic energy of the block = E₁

Force applied on the block = F = 9 N

Time period the force is applied = T = 2 sec

Impulse of the force on the block = I

Change in momentum of the block =

Impulse on an object is equal to the change in momentum of the object.

Final momentum of the block = P₂

Final velocity of the block = V₂

Final kinetic energy of the block = E₂

a) Initial momentum of the block = 15 kg.m/s

b) Initial kinetic energy of the block = 22.5 J

c) Change in momentum of the block = 18 kg.m/s

d) Final momentum of the block = 33 kg.m/s

e) Final velocity of the block = 6.6 m/s

f) Final kinetic energy of the block = 108.9 J

genius_generous answered 10 months ago

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