In: Statistics and Probability
Consider the following hypothesis test.
H0: μ ≤ 25 |
Ha: μ > 25 |
A sample of 40 provided a sample mean of 26.4. The population standard deviation is 6.
(a)
Find the value of the test statistic. (Round your answer to two decimal places.)
(b)
Find the p-value. (Round your answer to four decimal places.)
p-value =
(c)
At
α = 0.01,
state your conclusion.
Reject H0. There is sufficient evidence to conclude that μ > 25.Reject H0. There is insufficient evidence to conclude that μ > 25. Do not reject H0. There is sufficient evidence to conclude that μ > 25.Do not reject H0. There is insufficient evidence to conclude that μ > 25.
(d)
State the critical values for the rejection rule. (Round your answer to two decimal places. If the test is one-tailed, enter NONE for the unused tail.)
test statistic ≤test statistic ≥
State your conclusion.
Reject H0. There is sufficient evidence to conclude that μ > 25.Reject H0. There is insufficient evidence to conclude that μ > 25. Do not reject H0. There is sufficient evidence to conclude that μ > 25.Do not reject H0. There is insufficient evidence to conclude that μ > 25.
Solution :
= 25
= 26.4
= 6
n = 40
This is the right tailed test .
The null and alternative hypothesis is
H0 : ≤ 25
Ha : > 25
a) Test statistic = z
= ( - ) / / n
= (26.4 -25 ) /6 / 40
= 1.48
b) p(Z >1.48) = 1-P (Z <1.48 ) = 0.0694
P-value = 0.0694
= 0.05
0.0694> 0.05
c) Do not reject H0. There is insufficient evidence to conclude that μ > 25.
d) Do not reject H0. There is insufficient evidence to conclude that μ > 25.