In: Statistics and Probability
Consider the following hypothesis test.
H0: μ ≤ 12
Ha: μ > 12
A sample of 25 provided a sample mean
x = 14
and a sample standard deviation
s = 4.67.
A. Compute the value of the test statistic. (Round your answer to three decimal places.)
B. What is the rejection rule using the critical value? (If the test is one-tailed, enter NONE for the unused tail. Round your answer to three decimal places.)
test statistic≤test statistic≥
Solution :
= 12
=14
S =4.67
n = 25
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : ≤ 12
Ha : > 12
Test statistic = t
= ( - ) / S / n
= (12 - 14) / 4.67 / 25
= 2.141
Test statistic = t = 2.141
P-value =0.0213
It is observed that t=2.141 > tc =1.711, it is then concluded that the null hypothesis is rejected