In: Statistics and Probability
A snack food manufacturer estimates that the variance of the number of grams of carbohydrates in servings of its tortilla chips is
1.16 A dietician is asked to test this claim and finds that a random sample of 24 servings has a variance of 1.34. At ?=0.05?, is there enough evidence to reject the? manufacturer's claim? Assume the population is normally distributed.
Find the critical? value(s) and identify the rejection? region(s).
The critical? value(s) is(are) __
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis H0:
Alternative hypothesis HA:
Formulate an analysis plan. For this analysis, the significance level is 0.05.
Analyze sample data. Using sample data, the degrees of freedom (DF), and the test statistic (X2).
DF = n - 1 = 24 -1
D.F = 23
Rejection region is
Interpret results. Since the X2-value (30.69) is less than the critical value(35.17), we have to accept the null hypothesis.
From the above test we have sufficient evidence in the favor of the claim that the variance of the number of grams of carbohydrates in servings of its tortilla chips is 1.16.