a food snack manufacturer samples 13 bags of pretzels off the assembly line and weighs their...

a food snack manufacturer samples 13 bags of pretzels off the assembly line and weighs their contents. If the sample mean is 13.7 oz and the sample standard deviation is 0.05 oz find the 95% confidence interval true mean.

a. (13.4, 14.0)

b. (11.0, 16.0)

c. (11.4, 16.4)

d. (12.4, 15.0)

Solutions

Expert Solution

Solution :

Given that,

= 13.7

s =0.05

n =13 Degrees of freedom = df = n - 1 =13 - 1 = 12

At 95% confidence level the t is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2= 0.05 / 2 = 0.025

t /2,df = t0.025,12 = 2.179 ( using student t table)

Margin of error = E = t/2,df * (s / $\sqrt$ n)

= 2.179 * ( 2.17/ $\sqrt$ 13)

E = 1.3

The 95% confidence interval estimate of the population mean is,

- E < < + E

13.7 - 1.3< <13.7 + 1.3

12.4< < 15.0

( 12.4, 15.0 )

orchestra answered 1 year ago

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