In: Statistics and Probability
A normal distribution has μ = 32 and σ = 5.
(a) Find the z score corresponding to x = 27.
(b) Find the z score corresponding to x = 45.
(c) Find the raw score corresponding to z = −3.
(d) Find the raw score corresponding to z = 1.3.
Solution :
Given that,
mean = = 32
standard deviation = = 5
(a)
x = 27
z = x - / = 27 - 32 / 5 = -1
z score = -1
(b)
x = 45
z = x - / = 45 - 32 / 5 = 2.6
z score = 2.6
(c)
z = -3
Using z-score formula,
x = z * +
x = -3 * 5 + 32 = 17
raw score = 17
(d)
z = 1.3
Using z-score formula,
x = z * +
x = 1.3 * 5 + 32 = 38.5
raw score = 38.5