In: Chemistry
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical reaction: ?+S8s24F2g8SF6g Round your answer to zero decimal places.
Sol:-
Note :- (1).Standard Free energy of formation of S8 (g) ( i.e deltaG0f of S8 (s) ) = 0 KJ/mol
(2). Standard Free energy of formation of F2 (g) ( i.e deltaG0f of F2 (g)? ) = 0 KJ/mol and
(3). Standard Free energy of formation of SF6 (g) ( i.e deltaG0f of SF6? (g) ) = - 1116.4 KJ/mol
Given equation is :-
S8 (s) + 24 F2 (g) ----------------> 8 SF6 (g) , deltaGrxn0 = ?
we know
deltaGrxn0 = [Sum of Standard Free energy of formation of products ] - [ Sum of Standard Free energy of formation of reactants ]
deltaGrxn0 = [ 8 x deltaG0f of SF6? (g) ] - [ 1 x deltaG0f of S8 (s) + 24 x deltaG0f of F2 (g) ]
deltaGrxn0 = [ 8 x ( - 1116.4 KJ/mol ] - [ 1 x 0 KJ/mol + 24 x 0 KJ/mol ]
deltaGrxn0 = - 8931.2 KJ/mol - 0 KJ/mol
deltaGrxn0 = - 8931.2 KJ/mol
Hence Standard free energy of the reaction i.e deltaGrxn0 = - 8931.2 KJ/mol