In: Chemistry
Given the following bond-dissociation energies, calculate the average bond enthalpy for the Ti-Cl bond.
Average bond energy of Ti-C1 bond:
TiC14(g) → TiC13(g) + C1(g) ΔH = 335kJ
TiCl3(g) → TiCl2(g) + Cl(g) ΔH = 423 kJ
TiCl2(g) → TiCl(g) + Cl(g) ΔH = 444 kJ
TiCl(g) → Ti(g) + Cl(g) ΔH = 519 kJ
ΔH = 1721 kJ
Average Ti-Cl bond = 1721 kJ/4
= 430.25 kJ
Average bond enthalpy of Ti-Cl = 430 kJ.
Average bond energy of Ti-C1 bond:
TiC14(g) → TiC13(g) + C1(g) ΔH = 335kJ
TiCl3(g) → TiCl2(g) + Cl(g) ΔH = 423 kJ